相关疑难解决方法(0)

在我的应用程序中,我使用StringBuilder使用此代码构建XML文件:

StringBuilder sb = new StringBuilder();
sb.Append("<?xml version=\"1.0\" encoding=\"utf-8\"?>" + Environment.NewLine);

sb.Append(String.Format("<{0}>{1}", _pluralCamelNotation, Environment.NewLine));
for (int index = 0; index < 3; index++)
{
    sb.Append(String.Format("\t<{0}>{1}", _singularCamelNotation, Environment.NewLine));
    foreach (DataType dataType in _allDataTypes)
    {
        sb.Append(String.Format("\t\t<{0}>{2}</{0}>{1}", dataType.CamelCaseNotation, Environment.NewLine, dataType.GetDummyData()));
    }
    sb.Append(String.Format("\t</{0}>{1}", _singularCamelNotation, Environment.NewLine));
}
sb.Append(String.Format("</{0}>{1}", _pluralCamelNotation, Environment.NewLine));

return sb.ToString();

如何使用LINQ执行相同的操作,如下所示:

PSEUDO-CODE:

var xdoc = new XDocument(
    new XDeclaration("1.0", "utf-8", null),
    for (int index = 0; index < 3; index++) {
        new XElement(_pluralCamelNotation,
            _allDataTypes.Select(datatype => new XElement(_singularCamelNotation,
                new XElement(datatype.CamelCaseNotation, …