相关疑难解决方法(0)

我想在数组中的所有项目中进行字符串替换.我有的是:

$row['c1'] = str_replace("&", "&", $row['c1']);
$row['c2'] = str_replace("&", "&", $row['c2']);
$row['c3'] = str_replace("&", "&", $row['c3']);
$row['c4'] = str_replace("&", "&", $row['c4']);   
$row['c5'] = str_replace("&", "&", $row['c5']);
$row['c6'] = str_replace("&", "&", $row['c6']);
$row['c7'] = str_replace("&", "&", $row['c7']);   
$row['c8'] = str_replace("&", "&", $row['c8']);
$row['c9'] = str_replace("&", "&", $row['c9']);
$row['c10'] = str_replace("&", "&", $row['c10']); 

如何用更少的代码实现这一目标？我认为foreach声明可行,例如:

$columns = array($row['c1'], $row['c2'], $row['c3'], $row['c4'], $row['c5'], $row['c6'], $row['c7'], $row['c8'], $row['c9'], $row['c10']);

foreach ( $columns as $value){
   $value   = str_replace("&", "&", $value);
}

但它不起作用.

我正在尝试在数组中添加一个字段并返回它,但据说var_dump,没有对数组进行任何更改.执行if块中的指令,数据似乎正确.

function addLength($toAdd, $added){
   $result = $toAdd;
    foreach ($result as $row) {
        foreach ($added as $key => $value) {
            if($key == $row['id'] ){
                $row['length'] = $value;   
            }
        } 
    }
    var_dump($result);
    return $result;
}