我需要将某个JSON字符串转换为Java对象.我正在使用Jackson进行JSON处理.我无法控制输入JSON(我从Web服务中读取).这是我的输入JSON:
{"wrapper":[{"id":"13","name":"Fred"}]}
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这是一个简化的用例:
private void tryReading() {
String jsonStr = "{\"wrapper\"\:[{\"id\":\"13\",\"name\":\"Fred\"}]}";
ObjectMapper mapper = new ObjectMapper();
Wrapper wrapper = null;
try {
wrapper = mapper.readValue(jsonStr , Wrapper.class);
} catch (Exception e) {
e.printStackTrace();
}
System.out.println("wrapper = " + wrapper);
}
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我的实体类是:
public Class Student {
private String name;
private String id;
//getters & setters for name & id here
}
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My Wrapper类基本上是一个容器对象,用于获取我的学生列表:
public Class Wrapper {
private List<Student> students;
//getters & setters here
}
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我一直收到这个错误,"包装"返回null.我不确定缺少什么.有人可以帮忙吗?
org.codehaus.jackson.map.exc.UnrecognizedPropertyException:
Unrecognized field …Run Code Online (Sandbox Code Playgroud) 我有String以下值:
[
{
"key1": "value11",
"key2": "value12"
},
{
"key1": "value21",
"key2": "value22"
}
]
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以下课程:
public class SomeClass {
private String key1;
private String key2;
/* ... getters and setters omitted ...*/
}
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我想将它解析为a List<SomeClass>或aSomeClass[]
使用杰克逊 这是最简单的方法ObjectMapper吗?
我在使用 Jackson 序列化为 XML 时似乎遇到了问题。我的代码如下:
测试容器
package com.test;
import java.util.ArrayList;
import com.fasterxml.jackson.annotation.JsonProperty;
public class TestContainer {
private String testContainerID;
private String testContainerMessage;
private ArrayList<TestChild> testContainerChildren;
@JsonProperty("TestContainerID")
public String getTestContainerID() {
return testContainerID;
}
@JsonProperty("TestContainerID")
public void setTestContainerID(String testContainerID) {
this.testContainerID = testContainerID;
}
@JsonProperty("TestContainerMessage")
public String getTestContainerMessage() {
return testContainerMessage;
}
@JsonProperty("TestContainerMessage")
public void setTestContainerMessage(String testContainerMessage) {
this.testContainerMessage = testContainerMessage;
}
@JsonProperty("TestContainerChildren")
public ArrayList<TestChild> getTestContainerChildren() {
return testContainerChildren;
}
@JsonProperty("TestContainerChildren")
public void setTestContainerChildren(ArrayList<TestChild> testContainerChildren) {
this.testContainerChildren = testContainerChildren;
}
} …Run Code Online (Sandbox Code Playgroud)