在python中,生成HTML文档的最优雅方式是什么.我目前手动将所有标签附加到一个巨大的字符串,并将其写入文件.有更优雅的方式吗？
我纯粹使用Django来创建模板(没有服务器).这是我的计划:
page1.html
{% extends "base.html" %}
{% block 'body' %}
<div class="container">
<img src="./images/{{filename}}" style="padding-top:100px; padding-left:100px" align="center" width="60%" heig
</div>
{% endblock %}
base.html文件
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<link rel="stylesheet" type="text/css" href="../src/bootstrap.min.css">
<link rel="stylesheet" type="text/css" href="../src/sticky-footer-navbar.css">
<link rel="icon" href="../images/favicon.ico">
<title>MY TITLE</title>
</head>
<body>
<!-- Fixed navbar -->
<nav class="navbar navbar-default navbar-fixed-top">
<div class="container">
<div class="navbar-header">
<button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#navbar" aria-expanded="false" aria-controls="navbar">
<span class="sr-only">Toggle navigation</span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
<a class="navbar-brand" …我正在使用 Django，我需要从给定的模板 (lab.html) 动态生成一个 HTML 文件：
from django.template import Template, Context
from django.conf import settings
settings.configure()
f = qc.QFile('lab.html')
f.open(qc.QFile.ReadOnly | qc.QFile.Text)
stream = qc.QTextStream(f)
template = stream.readAll()
print(template)
f.close()
t = Template(template)
c = Context({"result": "test"}) #result is the variable in the html file that I am trying to replace
但是，我不断收到这个奇怪的错误，经过一些研究，我在任何地方都找不到。有什么想法吗？
Traceback (most recent call last):
File "/Users/gustavorangel/PycharmProjects/help/HelpUI.py", line 262, in filesSearch
t = Template(template)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/django/template/base.py", line 184, in __init__
engine = Engine.get_default()
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/django/template/engine.py", line 83, in …我正在构建一个应用程序,它使用Django模板引擎/语言来"编译"一些HTML.但是,该应用程序不能在Django上运行,并且没有所有的配置和东西.当我尝试使用它时,我收到以下错误:
Traceback (most recent call last):
File "Send.py", line 33, in <module>
template = loader.get_template("email.html")
File "/Library/Python/2.7/site-packages/django/template/loader.py", line 157, in get_template
template, origin = find_template(template_name)
File "/Library/Python/2.7/site-packages/django/template/loader.py", line 138, in find_template
raise TemplateDoesNotExist(name)
django.template.base.TemplateDoesNotExist: email.html
我使用的代码如下:
from django.template import loader, Context
from django.conf import settings
template = loader.get_template("email.html")
rendered = template.render(data)
该模板与Python文件位于同一目录中.