相关疑难解决方法(0)

给定datetime.timePython中的值,是否有一种标准方法可以为其添加整数秒,例如11:34:59+ 3 = 11:35:02？

这些明显的想法不起作用:

>>> datetime.time(11, 34, 59) + 3
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'int'
>>> datetime.time(11, 34, 59) + datetime.timedelta(0, 3)
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.timedelta'
>>> datetime.time(11, 34, 59) + datetime.time(0, 0, 3)
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.time'

最后我写了这样的函数:

def add_secs_to_time(timeval, secs_to_add):
    secs = timeval.hour * 3600 + timeval.minute * 60 + timeval.second
    secs += secs_to_add
    return datetime.time(secs // 3600, …

如何使用这样的日期生成数组:

javascript miliseconds格式的时间戳,格式为2010.12.01 00:00:00至2010.12.12.30 23.59.59,步长为5分钟.

['2010.12.01 00:00:00', '2010.12.01 00:05:00','2010.12.01 00:10:00','2010.12.01 00:15:00', ...]