public class Company implements java.io.Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Short companyId;
@OneToOne(cascade=CascadeType.PERSIST)
private Address address;
private String companyName;
@OneToMany(fetch = FetchType.LAZY, mappedBy = "company",cascade=CascadeType.PERSIST)
private Set<Product> products = new HashSet<Product>(0);
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public class Product implements java.io.Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "productId", unique = true, nullable = false)
private Integer productId;
private Short branchId;
private String productName;
private String sku;
private String category; ------> I am …Run Code Online (Sandbox Code Playgroud) 我是JPA的新手,想要实现一个通用的JPA DAO,需要找到查询结果集的行数来实现分页.搜索网络后,我找不到切实可行的方法.以下是许多文章中建议的代码:
public <T> Long findCountByCriteria(CriteriaQuery<?> criteria) {
CriteriaBuilder builder = em.getCriteriaBuilder();
CriteriaQuery<Long> countCriteria = builder.createQuery(Long.class);
Root<?> entityRoot = countCriteria.from(criteria.getResultType());
countCriteria.select(builder.count(entityRoot));
countCriteria.where(criteria.getRestriction());
return em.createQuery(countCriteria).getSingleResult();
}
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但是,该代码在使用时不起作用join.有没有办法使用JPA Criteria API计算查询结果集的行数?
更新:这是创建CriteriaQuery的代码:
CriteriaQuery<T> queryDefinition = criteriaBuilder.createQuery(this.entityClass);
Root<T> root = queryDefinition.from(this.entityClass);
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并且可以将一些联接添加到根,直到执行查询为止:
public Predicate addPredicate(Root<T> root) {
Predicate predicate = getEntityManager().getCriteriaBuilder().ge(root.join(Entity_.someList).get("id"), 13);
return predicate;
}
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并且生成的异常如下:
org.hibernate.hql.ast.QuerySyntaxException:无效路径:'generatedAlias1.id'[从entity.Entity中选择count(generatedAlias0)为generatedAlias0,其中(generatedAlias0.id> = 13L)和((generatedAlias1.id <= 34L)) ]
其中generatedAlias1应该在Entity上,generatedAlias0应该在我加入的关联上.请注意,我正确实现了Join,因为当我执行不带计数查询的查询时,它执行时没有错误,并且Join正常工作但是当我尝试执行count查询时它会抛出异常.