相关疑难解决方法(0)

假设我有这个:

-record(my_record, {foo, bar, baz}).

Keyvalpairs = [{foo, val1},
               {bar, val2},
               {baz, val3}].

Foorecord = #my_record{foo=val1, bar=val2, baz=val3}.

如何将Keyvalpairs转换为Foorecord？