我有一个gridview包含a details button作为最后一列.
我的aspx:
<asp:GridView Width="100%" ID="gv_NotApplied" CssClass="datatable" AllowSorting="True"
runat="server" TabIndex="2" AutoGenerateColumns="False" AllowPaging="True" GridLines="None">
<Columns>
<asp:TemplateField HeaderText="serial">
<ItemTemplate>
<asp:Label ID="lblSerial" runat="server"></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:BoundField HeaderText="name" DataField="crs_name" />
<asp:BoundField HeaderText="lecturer" DataField="name" />
<asp:TemplateField HeaderText="details">
<ItemTemplate>
<asp:ImageButton ID="Ibtn_Details" runat="server" ImageUrl="~/Images/detail.png"
CommandArgument='<%#((GridViewRow)Container).RowIndex%>' CommandName="Detail"
CausesValidation="false" />
</ItemTemplate>
</asp:TemplateField>
</Columns>
<RowStyle VerticalAlign="Top" CssClass="row" />
</asp:GridView>
我想做的是:
当用户单击时details button,打开一个弹出窗口(对话框窗口).
在这个窗口中我想放入一些asp.net服务器控件(比如网格视图).所以我希望这个窗口启用/允许我访问后面代码中的那些控件.
我有一个ASP.NET页面,页面使用jQuery UI对话框.当用户单击页面中的按钮(btnGo)时,我将检查用户是否已登录.如果没有登录,我会显示登录的jQuery UI对话框.我用过这段代码:
<body>
<form id="form1" runat="server">
<div>
<br />
<asp:TextBox ID="txtModelId" runat="server" Text="12"></asp:TextBox><br />
<asp:Button ID="btnGo" runat="server" Text="Go" OnClick="btnGo_Click" />
<br />
<asp:Label ID="lblUserMsg" runat="server" Text="Label"></asp:Label></div>
<div id="divContentHolder">
<div class="demo">
<div id="dialog" title="Login with your User Account">
<p id="validateTips">Enter your EmailId & password</p>
<fieldset>
<label for="email">Email</label>
<input type="text" name="email" id="email" value="" class="text ui-widget-content ui-corner-all" />
<label for="password">Password</label>
<asp:TextBox ID="txtFirstName" CssClass="text ui-widget-content ui-corner-all" runat="server" Text=""></asp:TextBox>
<!-- <asp:Button ID="btnSingIn" runat="server" OnClick="btnSingIn_Click" Text="Button" /><br />-->
<asp:Button ID="btnLogin" runat="server" Text="Login" OnClick="btnLogin_Click" …