我正在尝试将networkx与Python一起使用.当我运行此程序时,它会收到此错误.有什么遗漏？
#!/usr/bin/env python
import networkx as nx
import matplotlib
import matplotlib.pyplot
import matplotlib.pyplot as plt
G=nx.Graph()
G.add_node(1)
G.add_nodes_from([2,3,4,5,6,7,8,9,10])
#nx.draw_graphviz(G)
#nx_write_dot(G, 'node.png')
nx.draw(G)
plt.savefig("/var/www/node.png")
Traceback (most recent call last):
File "graph.py", line 13, in <module>
nx.draw(G)
File "/usr/lib/pymodules/python2.5/networkx/drawing/nx_pylab.py", line 124, in draw
cf=pylab.gcf()
File "/usr/lib/pymodules/python2.5/matplotlib/pyplot.py", line 276, in gcf
return figure()
File "/usr/lib/pymodules/python2.5/matplotlib/pyplot.py", line 254, in figure
**kwargs)
File "/usr/lib/pymodules/python2.5/matplotlib/backends/backend_tkagg.py", line 90, in new_figure_manager
window = Tk.Tk()
File "/usr/lib/python2.5/lib-tk/Tkinter.py", line 1650, in __init__
self.tk = _tkinter.create(screenName, baseName, className, interactive, wantobjects, useTk, …我找到了平台模块,但它说它返回'Windows'并且它在我的机器上返回'Microsoft'.我注意到在stackoverflow的另一个线程中它有时返回'Vista'.
所以,问题是,如何实施？
if isWindows():
...
以前向兼容的方式？如果我必须检查"Vista"之类的东西,那么当下一个版本的Windows出现时它就会中断.
注意:声称这是一个重复的问题的答案实际上没有回答问题isWindows.他们回答"什么平台"的问题.由于存在许多种类的窗口,它们都没有全面地描述如何得到答案isWindows.
Matplotlib似乎需要$ DISPLAY环境变量,这意味着正在运行的X服务器.
某些Web托管服务不允许运行X服务器会话.
有没有办法在没有正在运行的X服务器的情况下使用matplotlib生成图形？
[username@hostname ~]$ python2.6
Python 2.6.5 (r265:79063, Nov 23 2010, 02:02:03)
[GCC 4.1.2 20080704 (Red Hat 4.1.2-48)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import matplotlib.pyplot as plt
>>> fig = plt.figure()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/home/username/lib/python2.6/matplotlib-1.0.1-py2.6-linux-i686.egg/matplotlib/pyplot.py", line 270, in figure
**kwargs)
File "/home/username/lib/python2.6/matplotlib-1.0.1-py2.6-linux-i686.egg/matplotlib/backends/backend_tkagg.py", line 80, in new_figure_manager
window = Tk.Tk()
File "/usr/local/lib/python2.6/lib-tk/Tkinter.py", line 1643, in __init__
self.tk = _tkinter.create(screenName, baseName, className, interactive, wantobjects, …