相关疑难解决方法(0)

我有一些像这样的代码:

class Foo {
    public double x;
}

void test() {
    Foo foo = new Foo();

    // Is this a valid way to test for zero? 'x' hasn't been set to anything yet.
    if (foo.x == 0) {

    }

    foo.x = 0.0;

    // Will the same test be valid?
    if (foo.x == 0) {

    }
}

我基本上希望将来避免被零除的例外.

谢谢

这个问题出现在这段代码之后(二进制搜索的实现).如果有人能告诉我为什么没有输出预期答案,我将不胜感激:

public static void main(String[] args){
    Double[] array = {0.0,1.0,2.0,3.0,4.0,5.0,6.0,7.0,8.0,9.0};
    BinarySearch s = new BinarySearch(array);
    System.out.println(s.searchNextHighest(2.0));
}

public BinarySearch(Double[] array){
    numbers = array;
}

public Integer searchNextHighest(Double y){
    return binarySearchNextHighest(0, numbers.length-1, y, numbers);
}

public Integer binarySearchNextHighest(int min, int max, Double target, Double[] array){
    int mid = (min+max)/2;

    if(target==array[mid]){ //Fails here
        return mid;
    }

    if(max<min){
        if(min>=array.length) return null;
        return mid;
    }

    if(target>array[mid]){
        return binarySearchNextHighest(mid+1, max, target, array);
    }else{
        return binarySearchNextHighest(min, mid-1, target, array);
    }
}

输出:1

我跟着一个调试器并且绝对肯定.在某个时刻,target = 2.0,mid = …