#include <iostream>
using namespace std;
int main()
{
char c1 = 0xab;
signed char c2 = 0xcd;
unsigned char c3 = 0xef;
cout << hex;
cout << c1 << endl;
cout << c2 << endl;
cout << c3 << endl;
}
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我预计输出如下:
ab
cd
ef
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然而,我一无所获.
我想这是因为cout总是将'char','signed char'和'unsigned char'视为字符而不是8位整数.但是,'char','signed char'和'unsigned char'都是完整的类型.
所以我的问题是:如何通过cout将字符输出为整数?
PS:static_cast(...)很难看,需要更多的工作来修剪额外的比特.