我在运行时获得了一个jar文件URL:
jar:file:///C:/proj/parser/jar/parser.jar!/test.xml
如何将其转换为有效路径:
C:/proj/parser/jar/parser.jar.
使用我已经试过File(URI),getPath(),getFile()是徒劳的.
I am trying to read a property file which is located within a jar file. I want to use File.separator as the application will run on multiple platforms. I am constructing the path as follows:
jarFilePath="jar:file:"+jarFile.getAbsolutePath()+"!"+jarPropertyFilePath; //jarPropertyFilePath is getting loaded from a class which is storing Constant JAR_PROPERTY_FILE_PATH.
fileURL= new URL(jarFilePath);
但是，仅当jarPropertyFilePath（jar中属性文件的固定位置）的形式为：
情况1：
public static final String JAR_PROPERTY_FILE_PATH = "/manifest/patchControl.properties";
情况2：
如果我按以下方式使用File.separator，它将给出java.net.MalformedURLException：否！
public static final String JAR_PROPERTY_FILE_PATH = File.separator+"manifest"+File.separator+"patchControl.properties";
在第一种情况（工作原理很好）中，调试时的最终URL如下：
jar:file:C:\MyWorkspace\FalconPatchInstaller\.\patches\DS661JDK1.8.jar!/manifest/patchControl.properties
在情况2（不起作用）中，调试时的最终URL如下：
jar:file:C:\MyWorkspace\FalconPatchInstaller\.\patches\DS661JDK1.8.jar!\manifest\patchControl.properties
如何将File.separator用于JAR_PROPERTY_FILE_PATH？