相关疑难解决方法(0)

假设我有两个Python模块,并且path_b在导入路径中:

# file: path_b/my_module.py
print "I was imported from ???"

#file: path_a/app.py
import my_module

是否可以查看模块的导入位置？我想要一个输出,如"我是从path_a/app.py导入的",如果我启动app.py(因为我需要文件名).

编辑: 为了更好地理解; 我可以写:

# file: path_b/my_module.py
def foo(file):
    print "I was imported from %s" % file

#file: path_a/app.py
import my_module
my_module.foo(__file__)

所以输出将是:

$> python path_app.py
I was imported from path_a/app.py

当我运行命令时：

pydoc django.views.generic

我得到错误：

problem in django.views.generic - 
<class 'django.core.exceptions.ImproperlyConfigured'>:
Requested setting DEFAULT_INDEX_TABLESPACE, 
but settings are not configured. You must either define 
the environment variable DJANGO_SETTINGS_MODULE or call 
settings.configure() before accessing settings

我如何获得pydoc文档django.views.generic？