相关疑难解决方法(0)

Java:如何使用UrlConnection通过授权发布请求?

我想向需要身份验证的服务器生成POST请求.我试着使用以下方法:

private synchronized String CreateNewProductPOST (String urlString, String encodedString, String title, String content, Double price, String tags) {

    String data = "product[title]=" + URLEncoder.encode(title) +
                "&product[content]=" + URLEncoder.encode(content) + 
                "&product[price]=" + URLEncoder.encode(price.toString()) +
                "&tags=" + tags;
    try {
        URL url = new URL(urlString);
        URLConnection conn;
        conn = url.openConnection();
        conn.setRequestProperty ("Authorization", "Basic " + encodedString);
        conn.setDoOutput(true);
        conn.setDoInput(true);
        OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
        wr.write(data);
        wr.flush(); 
        // Get the response 
        BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); 
        String line; 
        while ((line = rd.readLine()) != …
Run Code Online (Sandbox Code Playgroud)

java post authorization urlconnection httpconnection

34
推荐指数
3
解决办法
16万
查看次数

setRequestProperty抛出java.lang.IllegalStateException:连接后无法设置request属性

我得到了java.lang.IllegalStateException:

java.lang.IllegalStateException:setRequestProperty调用方法 后,无法在连接建立后设置请求属性url.openConnection();

这是我正在尝试的:

URL url = new URL("https://49.205.102.182:7070/obsplatform/api/v1/mediadevices/545b801ce37e69cc");
         urlConnection = (HttpsURLConnection) url
        .openConnection();
urlConnection.setRequestProperty("Content-Type","application/json");
Run Code Online (Sandbox Code Playgroud)

有什么建议吗?提前致谢.

android

9
推荐指数
2
解决办法
1万
查看次数

例外; 连接完成后无法设置请求属性; 发生在Android棒棒糖HTC M8上

我正在使用请求Java Web ServiceAndroid应用程序调用Soap.有一种方法可以通过应用程序调用,几乎在所有设备和三星设备中的Android版本Kit KatLollipop可以正常工作,但不适用于HTC M8 Lollipop更新设备.
以下是我的代码.

HttpTransportSE ht = new HttpTransportSE("URL");
SoapObject so = new SoapObject("Namespace", "Method");
try {
    SoapSerializationEnvelope se = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    so.addProperty("input1", data);
    data = se.getResponse().toString();//This is where Exception occurs

}catch(Exception ex){
    ex.printStackTrace();
}
Run Code Online (Sandbox Code Playgroud)

一个Exception试图让响应由注释指示和精确的时,会发生Exception如下.

java.lang.IllegalStateException: Cannot set request property after connection is made
at com.android.okhttp.internal.http.HttpURLConnectionImpl.setRequestProperty(HttpURLConnectionImpl.java:496)
at com.android.okhttp.internal.http.DelegatingHttpsURLConnection.setRequestProperty(DelegatingHttpsURLConnection.java:258)
at com.android.okhttp.internal.http.HttpsURLConnectionImpl.setRequestProperty(HttpsURLConnectionImpl.java:25)
at org.ksoap2.transport.ServiceConnectionSE.setRequestProperty(ServiceConnectionSE.java:101)
at org.ksoap2.transport.HttpTransportSE.call(HttpTransportSE.java:156)
at org.ksoap2.transport.HttpTransportSE.call(HttpTransportSE.java:116)
Run Code Online (Sandbox Code Playgroud)

我一直在寻找这个但是找不到合适的答案或解决方法.

我查找了
Ksoap2 Android …

java android web-services android-ksoap2 android-5.0-lollipop

5
推荐指数
1
解决办法
1307
查看次数