相关疑难解决方法(0)

我有一个格式为年 (int)、月 (int) 和日 (int) 的日期，例如，2018 年 10 月 12 日为 2018、10、12。

有没有办法可以使用带有这些整数的 C++ Chrono 库来确定我的“日期”是否是周末？

如果不是，那么实现这一目标的最简单的替代方法是什么？

我想制作一个不输入任何内容并返回上一个星期一的日期的程序。（我不在乎时区。我只担心公历）。我正在使用Howard Hinnant的日期。这是我目前正在做的事情：

#include <iostream>
#include <date/date.h>

int main() {

    auto todays_day = date::year_month_weekday(date::floor<date::days>(std::chrono::system_clock::now()));

    auto todays_date = date::floor<date::days>(std::chrono::system_clock::now());

    int offset = 0;

    auto weekday = todays_day.weekday();

    if(weekday == date::Tuesday)
        offset = 1;
    else if (weekday == date::Wednesday)
        offset = 2;
    else if (weekday == date::Thursday)
        offset = 3;
    else if (weekday == date::Friday)
        offset = 4;
    else if (weekday == date::Saturday)
        offset = 5;
    else if (weekday == date::Sunday)
        offset = 6;

    auto lastMonday = date::year_month_day(todays_date - date::days(offset));

    std::cout …

I am using C++ 14 and am trying to get the current day of week. After some reading I am using date.h by Howard E. Hinnant.

However I am struggling to get a day of the week (encoded as 0 thru 6).

Something like this prints out Thu:

 int main(void)
 {
     date::sys_days t;
     weekday wd{t};
     cout << wd << '\n';
 }

Many answers on this site regarding getting the current day of the week use chrono.

How can …