相关疑难解决方法(0)

我试图在PostgreSQL中持久化一个使用UUID作为主键的实体.我已经尝试将其作为简单的UUID持久化:

@Id
@Column(name = "customer_id")
private UUID id;

有了上面的内容,我收到了这个错误:

ERROR: column "customer_id" is of type uuid but expression is of type bytea
Hint: You will need to rewrite or cast the expression.
Position: 137

我也尝试将UUID作为byte []保持无效:

@Transient
private UUID id;

@Id
@Column(name = "customer_id")
@Access(AccessType.PROPERTY)
@Lob
protected byte[] getRowId() {
    return id.toString().getBytes();
}

protected void setRowId(byte[] rowId) {
    id = UUID.fromString(new String(rowId));
}

如果我删除@Lob,我得到的错误与上面发布的错误相同.但是应用@Lob后,错误会略有变化:

ERROR: column "customer_id" is of type uuid but expression is of type bigint
Hint: You will …

我不能让Hibernate使用java.util.UUID for PostgreSQL.

这是使用javax.persistence的映射.*annotations:

private UUID itemUuid;

@Column(name="item_uuid",columnDefinition="uuid NOT NULL")
public UUID getItemUuid() {
    return itemUuid;
}

public void setItemUuid(UUID itemUuid) {
    this.itemUuid = itemUuid;
}

当持久化对象时,我得到一个SQLGrammarException:

column "item_uuid" is of type uuid but expression is of type bytea at character 149

PostgreSQL版本是8.4.4
JDBC驱动程序--8.4.4-702(也试过9.0 - 同样的事情)
Hibernate版本是3.6,主要配置属性:

<property name="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</property>
<property name="hibernate.connection.driver_class">org.postgresql.Driver</property>
<property name="hibernate.connection.url">jdbc:postgresql://192.168.1.1/db_test</property>