我正在寻找一种方法来包含/排除文件模式并从os.walk()调用中排除目录.
这就是我现在正在做的事情:
import fnmatch
import os
includes = ['*.doc', '*.odt']
excludes = ['/home/paulo-freitas/Documents']
def _filter(paths):
matches = []
for path in paths:
append = None
for include in includes:
if os.path.isdir(path):
append = True
break
if fnmatch.fnmatch(path, include):
append = True
break
for exclude in excludes:
if os.path.isdir(path) and path == exclude:
append = False
break
if fnmatch.fnmatch(path, exclude):
append = False
break
if append:
matches.append(path)
return matches
for root, dirs, files in os.walk('/home/paulo-freitas'):
dirs[:] = _filter(map(lambda d: …Run Code Online (Sandbox Code Playgroud) 如何在给定目录及其子目录中递归替换给定替换的匹配?
import os
import re
from os.path import walk
for root, dirs, files in os.walk("/home/noa/Desktop/codes"):
for name in dirs:
re.search("dbname=noa user=noa", "dbname=masi user=masi")
// I am trying to replace here a given match in a file
Run Code Online (Sandbox Code Playgroud) 我想获得一个适用于我所拥有的正则表达式的文件列表.我想我应该使用os.walk,但我如何使用正则表达式?
谢谢.