在我网站上用户生成的帖子下,我有一个类似亚马逊的评级系统:
Was this review helpful to you: Yes | No
如果有投票,我会在上面显示结果,如下所示:
5 of 8 people found this reply helpful.
我想根据这些排名对帖子进行排序.如果您从最有帮助到最不实用的排名,您将如何订购以下帖子？
a) 1/1 = 100% helpful
b) 2/2 = 100% helpful
c) 999/1000 = 99.9% helpful
b) 3/4 = 75% helpful
e) 299/400 = 74.8% helpful
显然,它不能仅对有用的百分比进行排序,不知何故应该考虑总票数.是否有一种标准的方法可以做到这一点？
更新:
使用Charles的公式来计算Agresti-Coull的较低范围并对其进行排序,以上示例将如何排序:
1) 999/1000 (99.9%) = 95% likely to fall in 'helpfulness' range of 99.2% to 100%
2) 299/400 (74.8%) = 95% likely to fall in 'helpfulness' range of 69.6% to 79.3%
3) 3/4 …