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我如何派生一个具有带一些参数的构造函数的类？

//The construction in base class:
BaseClass::BaseClass(int inArgument) :
    m_args (inArgument) // where m_args is a public/protected member of the base class
{

}
//The construction of derived class:
DerivedClass::DerivedClass(int inArgument) :
    m_args (inArgument) // where m_args is a public/protected member of the derived class
{

}

编译后我得到:错误1错误C2512:'BaseClass':没有合适的默认构造函数可用

我是初学c ++程序员......

可能重复:
构造函数中这个奇怪的冒号成员语法是什么？

如果我在C++中定义如下所示的类:

class myclass
{
public: 
 myclass (unsigned int param) : param_ (param)
 {
 }

unsigned int param () const
{
 return param_;
}

private:
  unsigned int param_;
};

构造函数定义myclass (unsigned int param) : param_ (param)是什么: 代码的含义和好处？