相关疑难解决方法(0)

我正在开发一个应用程序,我需要屏幕DPI ..我检查了几个论坛,并获得了一个代码片段,如下所示:

Dimension screen = java.awt.Toolkit.getDefaultToolkit().getScreenSize();
System.out.println("screen width: "+screen.getWidth()); 
System.out.println("screen height: "+screen.getHeight()); 
int pixelPerInch=java.awt.Toolkit.getDefaultToolkit().getScreenResolution(); 
System.out.println("pixelPerInch: "+pixelPerInch); 

double height=screen.getHeight()/pixelPerInch; 
double width=screen.getWidth()/pixelPerInch; 
double x=Math.pow(height,2); 
double y=Math.pow(width,2); 

但无论屏幕分辨率的pixelPerInch值是多少,96 的值都保持不变.代码有什么问题？

我得到了另一个swt相同的代码,如下所示:

  import org.eclipse.swt.graphics.Device;
  import org.eclipse.swt.widgets.Display;
  import org.eclipse.swt.widgets.Shell;

  public class MainClass {
  public void run() {
  Display display = new Display();
  Shell shell = new Shell(display);
  shell.setText("Display Device");
  createContents(shell);
  shell.pack();
  shell.open();
  while (!shell.isDisposed()) {
    if (!display.readAndDispatch()) {
      display.sleep();
    }
  }
  display.dispose();
}

private void createContents(Shell shell) {
  Device device = shell.getDisplay(); …