相关疑难解决方法(0)

int main()
{
   std::stringstream s1("This is my string.");
   std::stringstream s2 = s1; // error, copying not allowed
}

我找不到为什么我不能复制stringstream的原因.你能提供一些参考吗？

在创建一个简单的异常类扩展(我可以更容易地构造错误消息)时,我将错误分解为以下简单代码:

#include <sstream>
#include <string>
class myCout {
public:
    std::stringstream ssOut;    // Removing this gets rid of error
    template <typename T> myCout& operator << (const T &x) {
        // Do some formatting
        return *this;
    }
};

class myErr : public myCout {
public:
    using myCout::operator<<;
};

int main(int argc, const char* argv[]) {
    throw myErr() << "ErrorMsg" << 1;
    myCout() << "Message Will Be Formatted";
    return 0;
}

在编译时,会产生以下错误:

1>C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\include\sstream(724): error C2248: 'std::basic_ios<_Elem,_Traits>::basic_ios' : cannot …