我正在使用Spring创建一个独立的Sava应用程序来处理JDBC访问.该应用程序在每次测试中都能正常工作,我决定需要一个jar来部署我们的客户端.
他们的类路径中可能没有spring,所以我使用maven-assembly-plugin来处理带有依赖项的jar创建.
但是,当我尝试运行该应用程序时:
java -jar target/myproject-0.0.1-SNAPSHOT-jar-with-dependencies.jar
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这会引发以下错误:
Exception in thread "main" org.springframework.beans.factory.parsing.BeanDefinitionParsingException: Configuration problem: Unable to locate Spring NamespaceHandler for XML schema namespace [http://www.springframework.org/schema/p]
Offending resource: class path resource [applicationContext.xml]
at org.springframework.beans.factory.parsing.FailFastProblemReporter.error(FailFastProblemReporter.java:68)
at org.springframework.beans.factory.parsing.ReaderContext.error(ReaderContext.java:85)
at org.springframework.beans.factory.parsing.ReaderContext.error(ReaderContext.java:80)
...and so on to the database access class of this project.
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applicationContext.xml文件位于projectbase/src/main/resources中.它放在目标/包名基础上.
applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<bean id="dataSourceDesenv" class="org.apache.commons.dbcp.BasicDataSource"... />
<bean id="simpleJdbcDaoSupport" class="org.springframework.jdbc.core.simple.SimpleJdbcDaoSupport"
p:dataSource-ref="dataSourceDesenv" />
<bean id="simpleJdbcTemplate" class="org.springframework.jdbc.core.simple.SimpleJdbcTemplate">
<constructor-arg ref="dataSourceDesenv" />
</bean>
</beans>
Run Code Online (Sandbox Code Playgroud) 我在eclipse中运行tomcat中的一些servlet代码.它一直很好,但今天我得到了错误Unable to locate Spring NamespaceHandler for XML schema namespace.完整错误如下所示:
SEVERE: Allocate exception for servlet RunServlet
org.springframework.beans.factory.parsing.BeanDefinitionParsingException: Configuration problem: Unable to locate Spring NamespaceHandler for XML schema namespace [http://www.springframework.org/schema/tx]
Offending resource: class path resource [spring/dao.xml]
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我已经看过有关此错误的其他问题,但我并不理解答案.
当我查看目标库时,我可以看到它spring-tx-3.0.5.RELEASE.jar在WEB-INF/lib.
谁能帮我吗?
非常感谢!
编辑:dao.xml开始:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-2.0.xsd">
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编辑:不确定这是否相关,但我正在研究mac book pro,最新的mac更新更新到Java 1.6,我刚刚将我的Java首选项切换到1.6.
编辑:我也在Tomcat日志中收到以下消息,但我认为我以前收到它并且我认为它不相关,但以防万一:
INFO: Starting Servlet Engine: Apache Tomcat/7.0.14
Jul 6, 2011 11:59:55 AM org.apache.catalina.loader.WebappClassLoader validateJarFile
INFO: validateJarFile(/Users/bw/Documents/workspace2/.metadata/.plugins/org.eclipse.wst.server.core/tmp0/wtpwebapps/core/WEB-INF/lib/servlet-api-2.5.jar) - jar …Run Code Online (Sandbox Code Playgroud)