在Java中,有没有关于何时使用每个访问修饰符,即默认明确的规则(包私有)public
,protected
并且private
,同时使class
与interface
和处理继承?
a
只能在这里决赛.为什么?如何a
在onClick()
不将其保留为私有成员的情况下重新分配方法?
private void f(Button b, final int a){
b.addClickHandler(new ClickHandler() {
@Override
public void onClick(ClickEvent event) {
int b = a*5;
}
});
}
Run Code Online (Sandbox Code Playgroud)如何5 * a
点击它返回?我的意思是,
private void f(Button b, final int a){
b.addClickHandler(new ClickHandler() {
@Override
public void onClick(ClickEvent event) {
int b = a*5;
return b; // but return type is void
}
});
}
Run Code Online (Sandbox Code Playgroud)我一直在阅读一些有关Android内存泄漏的文章,并观看了Google I/O 关于此主题的有趣视频.
尽管如此,我还是不完全理解这个概念,特别是当在Activity中使用内部类是安全或危险的时候.
这就是我的理解:
如果内部类的实例比其外部类(活动)存活的时间更长,则会发生内存泄漏.- > 在哪种情况下会发生这种情况?
在这个例子中,我认为没有泄漏的风险,因为匿名类扩展没有办法OnClickListener
比活动更长寿,对吧?
final Dialog dialog = new Dialog(this);
dialog.setContentView(R.layout.dialog_generic);
Button okButton = (Button) dialog.findViewById(R.id.dialog_button_ok);
TextView titleTv = (TextView) dialog.findViewById(R.id.dialog_generic_title);
// *** Handle button click
okButton.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
dialog.dismiss();
}
});
titleTv.setText("dialog title");
dialog.show();
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现在,这个例子是危险的,为什么?
// We are still inside an Activity
_handlerToDelayDroidMove = new Handler();
_handlerToDelayDroidMove.postDelayed(_droidPlayRunnable, 10000);
private Runnable _droidPlayRunnable = new Runnable() {
public void run() {
_someFieldOfTheActivity.performLongCalculation(); …
Run Code Online (Sandbox Code Playgroud) 我有以下代码:
class Hello {
class Thing {
public int size;
Thing() {
size = 0;
}
}
public static void main(String[] args) {
Thing thing1 = new Thing();
System.out.println("Hello, World!");
}
}
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我知道Thing
什么都不做,但我的Hello,World程序在没有它的情况下编译得很好.这只是我定义的类失败了.
它拒绝编译.我开始No enclosing instance of type Hello is accessible."
创造一个新的东西.我猜是:
有任何想法吗?
所以标题说明了一切.我的内部出现了编译错误onClick
.
这是代码.
public class fieldsActivity extends Activity {
Button addSiteButton;
Button cancelButton;
Button signInButton;
/**
* Called when the activity is first created.
*/
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
// to create a custom title bar for activity window
requestWindowFeature(Window.FEATURE_CUSTOM_TITLE);
setContentView(R.layout.fields);
// use custom layout title bar
getWindow().setFeatureInt(Window.FEATURE_CUSTOM_TITLE, R.layout.topbar);
Pager adapter = new Pager();
ViewPager mPager = (ViewPager) findViewById(R.id.fieldspager);
mPager.setAdapter(adapter);
mPager.setCurrentItem(1);
addSiteButton = (Button) findViewById(R.id.addSiteButton);
addSiteButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
mPager.setCurrentItem(2, true); …
Run Code Online (Sandbox Code Playgroud) 我正在努力解决这个错误:
08-08 11:42:53.179:E/AndroidRuntime(20288):引起:java.lang.InstantiationException:无法实例化类com.example.localnotificationtest.ReminderService; 没有空的构造函数
我不明白为什么会出现这种错误.
我试图在特定时间出现通知,并在搜索一段时间后,我发现这个旧的stackoverflow问题.我尝试了一切,但我的代码给出了错误.
请帮我解决这个问题.
这是我的MainActivity代码:
public class MainActivity extends Activity {
int mHour, mMinute;
ReminderService reminderService;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
reminderService = new ReminderService("ReminderService");
TimePickerDialog dialog = new TimePickerDialog(this, mTimeSetListener, mHour, mMinute, false);
dialog.show();
}
TimePickerDialog.OnTimeSetListener mTimeSetListener = new OnTimeSetListener() {
@Override
public void onTimeSet(TimePicker v, int hourOfDay, int minute) {
mHour = hourOfDay;
mMinute = minute;
AlarmManager alarmManager = (AlarmManager)getSystemService(ALARM_SERVICE);
Calendar c = Calendar.getInstance();
c.set(Calendar.YEAR, Calendar.YEAR);
c.set(Calendar.MONTH, Calendar.MONTH);
c.set(Calendar.DAY_OF_MONTH, Calendar.DAY_OF_MONTH); …
Run Code Online (Sandbox Code Playgroud) 请参阅下面的代码段:
代码1
public class A {
static int add(int i, int j) {
return(i + j);
}
}
public class B extends A {
public static void main(String args[]) {
short s = 9;
System.out.println(add(s, 6));
}
}
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代码2
public class A {
int add(int i, int j) {
return(i + j);
}
}
public class B extends A {
public static void main(String args[]) {
A a = new A();
short s = 9;
System.out.println(a.add(s, 6));
}
}
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这些代码片段有什么区别?两者都 …
我今天在阅读Accelerated GWT(Gupta)时遇到了这段代码- 第151页.
public static void getListOfBooks(String category, BookStore bookStore) {
serviceInstance.getBooks(category, bookStore.new BookListUpdaterCallback());
}
public static void storeOrder(List books, String userName, BookStore bookStore) {
serviceInstance.storeOrder(books, userName, bookStore.new StoreOrderCallback());
}
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这些新运营商在那里做什么?我从未见过这样的语法,任何人都可以解释一下吗?
有谁知道在java规范中哪里可以找到这个?
java ×10
android ×3
memory-leaks ×1
private ×1
protected ×1
public ×1
static ×1
static-class ×1
syntax ×1