相关疑难解决方法(0)

以下代码在第2行接收seg错误:

char *str = "string";
str[0] = 'z';  // could be also written as *str = 'z'
printf("%s\n", str);

虽然这非常有效:

char str[] = "string";
str[0] = 'z';
printf("%s\n", str);

经过MSVC和GCC测试.

我正在使用strchr在缓冲区中找到=遇到的点.然后我正在改变那个相同的角色而不是a M.我在尝试执行此操作的行中遇到了段错误.

这是完整的代码:

int main(void){
    char *buffer = "Name=Tom"
    char *pointer;
    pointer = strchr(buffer,'=');
    *pointer = 'M';    <--------- Segfault Occurs here
return (0);
}

我在segfault中遇到以下错误:

Process terminating with default action of signal 11 (SIGSEGV)
 Bad permissions for mapperd region at addresss .....