相关疑难解决方法(0)

我正在将Foo对象列表转换为JSON字符串.我需要将JSON字符串解析回Foos列表.但是在下面的示例中,解析为我提供了JSONObjects而不是Foos的列表.

例

List list = [new Foo("first"), new Foo("second")]
def jsonString = (list as JSON).toString()

List parsedList = JSON.parse(jsonString) as List
println parsedList[0].getClass() // org.codehaus.groovy.grails.web.json.JSONObject

我怎样才能把它解析成Foos呢？提前致谢.

以下是我的 JSON 响应数据，我需要使用以下响应进行断言。我尝试了很多方法来编写 JSON 路径和期望值。总是断言失败。我想要的是请帮助写下以下数据的路径和期望值

{
    "statusCode": 200,
    "statusMessage": "Success",
    "errorMessage": "",
    "responseData": {
        "id": 15,
        "userName": "partner@tarento.com",
        "firstName": "tarento",
        "lastName": "test1",
        "phoneNumber": "1234567812",
        "email": "partner@tarento.com",
        "password": "",
        "city": "",
        "agentList": [
            {
                "id": 37,
                "userName": "Rahul.antonyRaj@tarento.com",
                "firstName": "Sanjay",
                "lastName": "rahul",
                "phoneNumber": "7411269480",
                "email": "Rahul.antonyRaj@tarento.com",
                "password": "",
                "active": true
            },
            {
                "id": 68,
                "userName": "jinesh.sumedhan@tareto.com",
                "firstName": "jinesh",
                "lastName": "sumedhan",
                "phoneNumber": "9400993826",
                "email": "jinesh.sumedhan@tareto.com",
                "password": "",
                "active": true
            },
            {
                "id": 108,
                "userName": "a.sanjayrahul@gmail.com",
                "firstName": "Rahul",
                "lastName": "Antony",
                "phoneNumber": "9994590241",
                "email": …

我的java.lang.String的形式

 [[{"ABC":{"total":0,"failed":0,"skipped":0}}], [{"BCD": {"total":0,"failed":0,"skipped":0}}]]

如何在Groovy中将其转换为json？