相关疑难解决方法(0)

我有一个由Java 8流表示的数据集:

Stream<T> stream = ...;

我可以看到如何过滤它以获得随机子集 - 例如

Random r = new Random();
PrimitiveIterator.OfInt coin = r.ints(0, 2).iterator();   
Stream<T> heads = stream.filter((x) -> (coin.nextInt() == 0));

我还可以看到如何减少此流以获得,例如,两个列表代表数据集的两个随机半部分,然后将它们转换回流.但是,有没有直接的方法从最初的流生成两个流？就像是

(heads, tails) = stream.[some kind of split based on filter]

感谢您的任何见解.

我如何使用java-8的Stream方法拆分奇数和偶数并在集合中求和？

public class SplitAndSumOddEven {

public static void main(String[] args) {

    // Read the input
    try (Scanner scanner = new Scanner(System.in)) {
        // Read the number of inputs needs to read.
        int length = scanner.nextInt();
        // Fillup the list of inputs
        List<Integer> inputList = new ArrayList<>();
        for (int i = 0; i < length; i++) {
            inputList.add(scanner.nextInt());
        }
        // TODO:: operate on inputs and produce output as output map
        Map<Boolean, Integer> oddAndEvenSums = inputList.stream(); \\here I want to split odd …