相关疑难解决方法(0)

使用Web API并使用swashbuckle生成swagger文档,我在两个不同的命名空间中定义了两个具有相同名称的不同类.当我在浏览器中打开swagger页面时说

冲突的schemaIds:为类型A和B检测到重复的schemaId.请参阅配置设置 - "UseFullTypeNameInSchemaIds"以获取潜在的解决方法

完整消息:

500:{"消息":"发生了错误.","ExceptionMessage":"冲突的schemaIds:为类型A和B检测到重复的schemaIds.请参阅配置设置 - \"UseFullTypeNameInSchemaIds \"以获取潜在的解决方法","ExceptionType ":"System.InvalidOperationException","StackTrace":"在Swashbuckle.Swagger.SchemaRegistry.CreateRefSchema(类型类型)\ r \n,在Swashbuckle.Swagger.Swagger.SchemaRegistry.CreateInlineSchema(类型类型)\ r \n在Swashbuckle.Swagger. SchemaRegistry.b__1f(JsonProperty prop)\ r \n在System.Linq.Enumerable.ToDictionary [TSource,TKey,TElement](IEnumerable 1 source, Func2 keySelector,Func 2 elementSelector, IEqualityComparer1 comparer )\ r \n在Swashbuckle.Swagger.SchemaRegistry.CreateObjectSchema(JsonObjectContract jsonContract) )\ r \n at Swashbuckle.Swagger.SchemaRegistry.CreateDefinitionSchema(Type type)\ r \n at Swashbuckle.Swagger.SchemaRegistry.GetOrRegister(Type type)\ r \n at Swashbuckle.Swagger.SwaggerGenerator.CreateOperation(ApiDescription apiDesc,SchemaRegistry) schemaRegistry)\ r \n在Swashbuckle.Swagger.SwaggerGenerator.CreateP athItem(IEnumerable的1 apiDescriptions, SchemaRegistry schemaRegistry)\r\n at Swashbuckle.Swagger.SwaggerGenerator.<>c__DisplayClass7.<GetSwagger>b__4(IGrouping2组)\ r \n在System.Linq.Enumerable.ToDictionary [TSource,TKEY的,TElement](IEnumerable的1 source, Func2的KeySelector,Func键2 elementSelector, IEqualityComparer1比较器)\ r \n在Swashbuckle.Swagger.SwaggerGenerator.GetSwagger(字符串使用rootUrl,字符串apiVersion)\ r \n在Swashbuckle.Application.SwaggerDocsHandler.SendAsync(HttpRequestMessage请求,CancellationToken cancellationToken)\ r \n在System.Net.Http.MttageInvoker.SendAsync(HttpRequestMessage请求,CancellationToken cancellationToken)\ …