相关疑难解决方法(0)

有两组堆栈导航器；

const SetOneScreens = () => (
  <Stack.Navigator initialRouteName="AScreen">
    <Stack.Screen name="AScreen" component={AScreen} />
    <Stack.Screen name="BScreen" component={BScreen} />
  </Stack.Navigator>
);
const SetTwoScreens = () => (
  <Stack.Navigator initialRouteName="CScreen">
    <Stack.Screen name="CScreen" component={CScreen} />
    <Stack.Screen name="DScreen" component={DScreen} />
  </Stack.Navigator>
);

哪些嵌套在抽屉导航器中

    <NavigationContainer>
      <Drawer.Navigator initialRouteName="SetOneScreens">
        <Drawer.Screen name="SetOneScreens" component={SetOneScreens} />
        <Drawer.Screen name="SetTwoScreens" component={SetTwoScreens} options={{swipeEnabled: false}} />
      </Drawer.Navigator>
    </NavigationContainer>

我想从导航BScreen到DScreen并重置堆栈（为了不让android中的硬件后退按钮返回BScreen）

在嵌套的情况下，我们应该首先定义导航器名称；我应该如何在重置操作中定义屏幕。

// For navigation 
props.navigation.navigate('setTwoScreens',{screen:'DScreen'})

// For reset I can only navigate to initial screen 
props.navigation.reset({index:0,routes:[{name:'setTwoScreens'}]})

我应该如何处理resetwithnavigation …