我似乎无法从PDO收到任何错误消息:
#$dbh->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING );
try {
$sth = $dbh->prepare('@$%T$!!!');
print_r($sth);
print_r($dbh->errorInfo());
} catch (PDOException $e) {
echo $e->getMessage();
}
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它只给出:
PDOStatement Object
(
[queryString] => @$%T$!!!
)
Array
(
[0] => 00000
[1] =>
[2] =>
)
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setAttribute没有任何帮助.
这是PHP 5.3.3
支持MySQL的Apache 2.0 Handler PDO驱动程序
客户端API版本mysqlnd 5.0.7-dev - 091210 - $ Revision:300533 $
我该怎么做才能获得错误信息?
这是我的PHP sql语句,它在var转储时返回false
$password_md5 = md5($_GET['password']);
$sql = $dbh->prepare('INSERT INTO users(full_name, e_mail, username, password, password_plain) VALUES (:fullname, :email, :username, :password, :password_plain)');
$result = $sql->execute(array(
':fullname' => $_GET['fullname'],
':email' => $_GET['email'],
':username' => $_GET['username'],
':password' => $password_md5,
':password_plain' => $_GET['password']));
Run Code Online (Sandbox Code Playgroud) 我正在PHP PDO中编写一个用户注册函数,我发现只有在这样写的情况下我的查询才能正常运行:
<?php
$dbHost="localhost";
$dbName="project";
$dbUser="admin";
$dbPassword="abcd";
$dbh=new PDO("mysql:host=$dbHost;dbName=$dbName", $dbUser, $dbPassword);
$dbh->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
$query=$dbh->prepare("INSERT INTO project.users (userName, userEmail) VALUES (?,?)");
.....
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另一方面,如果我写,它将无法运行:
...
$query=$dbh->prepare("INSERT INTO users (userName, userEmail) VALUES (?,?)");
...
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在这种情况下,我收到以下错误消息:
致命错误:未捕获异常'PDOException',消息'SQLSTATE [3D000]:无效的目录名称:1046未选择数据库'在C:\ wamp\www\Tests\Test03\Index.php:11堆栈跟踪:#0 C:\ wamp\www\Tests\Test03\Index.php(11):PDOStatement-> execute()#1 {main}在第11行的C:\ wamp\www\Tests\Test03\Index.php中抛出
为什么我需要精确project.users?为什么输入表名不够,因为db名称本身已经在PDO对象中了?
谢谢!
JDelage
更新 请参阅下面接受的答案.更换dbName=$dbName用dbname=$dbName解决了这个问题.