相关疑难解决方法(0)

我有一个Recipe代表此 YAML 块的类：

id: Ex1
  uses:
    - Database: ["D1", "D2"]
    - MetaFeature: ["M1", "M2"]
    - Algorithm: ["A1", "A2"]
    - Config: ["C1", "C4"]

id: Ex1
  uses:
    - Database: ["D1", "D2"]
    - MetaFeature: ["M1", "M2"]
    - Algorithm: ["A1", "A2"]
    - Config: ["C1", "C4"]

有没有办法将此 YAML 解析为 Recipe 类，而无需创建其他类或执行一些技巧？