相关疑难解决方法(0)

我正在做Rust示例教程,其中包含以下代码片段:

// Vec example
let vec1 = vec![1, 2, 3];
let vec2 = vec![4, 5, 6];

// `iter()` for vecs yields `&i32`. Destructure to `i32`.
println!("2 in vec1: {}", vec1.iter()     .any(|&x| x == 2));
// `into_iter()` for vecs yields `i32`. No destructuring required.
println!("2 in vec2: {}", vec2.into_iter().any(| x| x == 2));

// Array example
let array1 = [1, 2, 3];
let array2 = [4, 5, 6];

// `iter()` for arrays yields `&i32`.
println!("2 in array1: {}", array1.iter() …

我来自C(在较小程度上,C++)背景.我写了以下代码片段:

fn main() {
    let my_array = [1, 2, 3];
    let print_me = |j| println!("= {}", j);
    for k in my_array.iter() {
        print_me(k);
    }
}

这编译并按预期运行,但后来我指定了传递给闭包的参数的类型print_me:

fn main() {
    let my_array = [1, 2, 3];
    let print_me = |j: i32| println!("= {}", j);
    for k in my_array.iter() {
        print_me(k);
    }
}

我收到了编译错误:

error[E0308]: mismatched types
 --> src/main.rs:6:22
  |
6 |             print_me(k);
  |                      ^
  |                      |
  |                      expected i32, found &{integer}
  |                      help: consider dereferencing the borrow: `*k`
  | …