相关疑难解决方法(0)

根据我的项目提供商org.glassfish.json.JsonProviderImpl未找到我不明白为什么它抱怨glassfish因为我正在为json使用另一个库:

...
        <dependencies>
            <dependency>
                <groupId>javax.servlet</groupId>
                <artifactId>javax.servlet-api</artifactId>
                <version>3.0.1</version>
                <scope>provided</scope>
            </dependency>
            <dependency>
                <groupId>javax.websocket</groupId>
                <artifactId>javax.websocket-api</artifactId>
                <version>1.1</version>
                <scope>provided</scope>
            </dependency>
            <dependency>
                <groupId>javax.json</groupId>
                <artifactId>javax.json-api</artifactId>
                <version>1.0</version>
            </dependency>
            <dependency>
                <groupId>mysql</groupId>
                <artifactId>mysql-connector-java</artifactId>
                <version>5.1.36</version>
            </dependency>
        </dependencies>
...

关于如何使用我的Json库并避免使用glassfish的任何想法？

如何在eclipse中运行Java API for JSON Processing(JSR 374)？

我试图将JSON字符串解析为JsonParser(javax.json.stream.JsonParser).还在构建路径中添加了javax.json-api-1.0.jar.在运行时,有一个例外.我的代码是

import java.io.StringReader;
import javax.json.Json;
import javax.json.JsonReader;
import javax.json.JsonStructure;
import javax.json.stream.JsonParser;
import javax.json.stream.JsonParser.Event;
import javax.json.JsonReader;
import javax.json.JsonStructure;
import javax.json.stream.JsonParser;
import javax.json.stream.JsonParser.Event;
public class jsonnn {
public class jsonnn {
public static void main(String[] args) {
        // Parse back
        final String result = "{\"name\":\"Falco\",\"age\":3,\"bitable\":false}";
        final JsonParser parser = Json.createParser(new StringReader(result));
        String key = null;
        String value = null;
        while (parser.hasNext()) {
            final Event event = parser.next();
            switch (event) {
            case KEY_NAME:
                key = parser.getString();
                System.out.println(key); …