相关疑难解决方法(0)

我正在创建一个需要登录的应用程序.我创建了主要和登录活动.

在主要活动onCreate方法中,我添加了以下条件:

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    ...

    loadSettings();
    if(strSessionString == null)
    {
        login();
    }
    ...
}

onActivityResult登录表单终止时执行的方法如下所示:

@Override
public void onActivityResult(int requestCode,
                             int resultCode,
                             Intent data)
{
    super.onActivityResult(requestCode, resultCode, data);
    switch(requestCode)
    {
        case(SHOW_SUBACTICITY_LOGIN):
        {
            if(resultCode == Activity.RESULT_OK)
            {

                strSessionString = data.getStringExtra(Login.SESSIONSTRING);
                connectionAvailable = true;
                strUsername = data.getStringExtra(Login.USERNAME);
            }
        }
    }

问题是登录表单有时会出现两次(login()方法被调用两次),当手机键盘滑动时,再次出现登录表单,我猜问题是变量strSessionString.

有没有人知道如何设置变量global以避免在用户已经成功验证后出现登录表单？

我有一个非常无聊的问题.当我的应用程序转到后台时,有时会在LogCat显示时终止该进程:

INFO/ActivityManager(187): Low Memory: No more background processes.
INFO/ActivityManager(187): Process com.app.myapp (pid 20681) has died.
INFO/WindowManager(187): WIN DEATH: Window{40592708 com.app.myapp/app.myapp.dashboard.Dashboard paused=false}
ERROR/InputDispatcher(187): channel '408b1d40 app.myapp/app.myapp.menus.products.Promotions (server)' ~ Consumer closed input channel or an error occurred.  events=0x8
ERROR/InputDispatcher(187): channel '408b1d40 app.myapp/app.myapp.menus.products.Promotions (server)' ~ Channel is unrecoverably broken and will be disposed!
INFO/WindowManager(187): WIN DEATH: Window{408b1d40 app.myapp/app.myapp.menus.products.Promotions paused=false}
INFO/ActivityManager(187): Starting: Intent { act=android.intent.action.MAIN cat=[android.intent.category.LAUNCHER] flg=0x10100000 cmp=app.myapp/.Main } from pid 187
INFO/ActivityManager(187): Start proc app.myapp for activity app.myapp/.menus.products.Promotions: pid=20721 uid=10062 gids={3003, 1015}

当我尝试返回应用程序时,通过任务切换器(长按回家),它会尝试返回上次打开的活动...并崩溃. …