相关疑难解决方法(0)

我已经设置了弹出窗口,但是我想将它放在按钮(View v)下面,需要点击它才能打开它:

public void showPopup(Context c, View v){
    int[] location = new int[2];
    v.getLocationOnScreen(location);

    ViewGroup base = (ViewGroup) getView().findViewById(R.id.pup_pattern);  
    LayoutInflater inflater = (LayoutInflater) c.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    View pupLayout = inflater.inflate(R.layout.linearlayout_popup, base);

    final PopupWindow pup = new PopupWindow(pupLayout, android.view.ViewGroup.LayoutParams.WRAP_CONTENT, android.view.ViewGroup.LayoutParams.WRAP_CONTENT);

    int x = location[0] - (int) ((pupLayout.getWidth() - v.getWidth()) / 2 ); // --> pupLayout.getWidth() gives back -2?
    int y = location[1] + v.getHeight() + 10;

    pup.setFocusable(true);
    pup.showAtLocation(v, Gravity.NO_GRAVITY, x, y);
}

有人有想法得到措施吗？