相关疑难解决方法(0)

是否有在Dart中进行urlencoding的功能？我正在使用XMLHttpRequest对象进行AJAX调用,我需要将url编码为url.

我在dartlang.org上搜索过,但没有找到任何结果.

我已将动态链接设置为文档，但单击链接时它显示：

Deep Link does not contain valid required params. URL params: {
"_cpb" = 1;
"_cpt" = cpit;
"_fpb" = "CJsFEPcCGgVlbi1VUw==";
"_iumchkactval" = 1;
"_iumenbl" = 1;
"_osl" = "https://ttnfleetsolutions.page.link/azrN2YkJQncowdQ78";
"_plt" = 3698;
"_uit" = 1651;
apn = "com.ttnfleetsolutions.ttnfleet.debug";
cid = 4103105643708739955;
ibi = "com.ttnfleetsolutions.ttnfleetCustomer";
link = "https://www.ttnfleetsolutions.com/";

}

单击动态链接时应用程序打开，但它不调用任何函数并显示错误如何知道链接是否被单击？

我用选项方法完成了午餐：

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool{
    IQKeyboardManager.shared.enable = true
    FirebaseApp.configure()       UIBarButtonItem.appearance().setTitleTextAttributes([NSAttributedString.Key.foregroundColor: UIColor.clear], for: .normal)
    UIBarButtonItem.appearance().setTitleTextAttributes([NSAttributedString.Key.foregroundColor: UIColor.clear], for: UIControl.State.highlighted)
    GMSServices.provideAPIKey(GOOGLE_API_KEY)
    GMSPlacesClient.provideAPIKey(GOOGLE_API_KEY)
return true

和文档中的函数：

@available(iOS 9.0, …