相关疑难解决方法(0)

我有以下SQL查询。

select colA, sum(colB) as colB from tableA group by colA order by colB desc;

我已经使用jpa条件构建器来动态构建查询。

List<String> selectCols = new ArrayList<>();
selectCols.add("colA");
List<String> sumColumns = new ArrayList<>();
sumColumns.add("colB");
List<String> groupByColumns = new ArrayList<>();
groupByColumns.add("colA");
List<String> orderingColumns = new ArrayList<>();
orderingColumns.add("colB");

CriteriaBuilder builder = entityManager.getCriteriaBuilder();
CriteriaQuery<Tuple> cQuery = builder.createQuery(Tuple.class);
Root<T> root = cQuery.from(getDomainClass());

List<Selection<?>> selections = new ArrayList<>();
for (String column : selectCols) {
    selections.add(root.get(column).alias(column));
}

if (sumColumns != null) {
    for (String sumColumn : sumColumns) {
        selections.add(builder.sum(root.get(sumColumn)).alias(sumColumn));
    }
}

cQuery.multiselect(selections); …