给定这个字符串:"Fri, 09 Apr 2010 14:10:50 +0000"如何将其转换为datetime对象？
做了一些阅读后,我觉得这应该有用,但它不...
>>> from datetime import datetime
>>>
>>> str = 'Fri, 09 Apr 2010 14:10:50 +0000'
>>> fmt = '%a, %d %b %Y %H:%M:%S %z'
>>> datetime.strptime(str, fmt)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib64/python2.6/_strptime.py", line 317, in _strptime
(bad_directive, format))
ValueError: 'z' is a bad directive in format '%a, %d %b %Y %H:%M:%S %z'
应该注意的是,这没有问题:
>>> from datetime import datetime
>>>
>>> str …继我之前的问题,Python的时间老化之后,我现在遇到了关于时区的问题,结果发现它并不总是"+0200".因此当strptime尝试解析它时,它会引发异常.
我想过用[:-6]或者其他什么来切断+0200,但有一种真正的方法可以用strptime做到这一点吗？
如果重要的话,我正在使用Python 2.5.2.
>>> from datetime import datetime
>>> fmt = "%a, %d %b %Y %H:%M:%S +0200"
>>> datetime.strptime("Tue, 22 Jul 2008 08:17:41 +0200", fmt)
datetime.datetime(2008, 7, 22, 8, 17, 41)
>>> datetime.strptime("Tue, 22 Jul 2008 08:17:41 +0300", fmt)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.5/_strptime.py", line 330, in strptime
(data_string, format))
ValueError: time data did not match format: data=Tue, 22 Jul 2008 08:17:41 +0300 fmt=%a, %d %b %Y %H:%M:%S +0200