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get_queryset中的Django 2.0 url参数

我想根据网址中的类别ID过滤子类别

对于恒定值,它可以正常工作

return Subcategory.objects.filter(category = 1)
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views.py

class SubcategoriesListView(ListView):
    model = Subcategory
    template_name = 'app/categories/index.html'
    def get_queryset(self):
        return Subcategory.objects.filter(category = category_id)
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urls.py

path('categories/<int:category_id>/', app.views.SubcategoriesListView.as_view(), name='subcategories'),
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models.py

class Subcategory(models.Model):
   title = models.CharField(max_length=30)
   category = models.ForeignKey(Category, on_delete=models.CASCADE)
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追溯

/ categories / 1 /处的NameError未定义名称'category_id'

get_queryset中的views.py返回Subcategory.objects.filter(category = category_id)

python django django-views

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