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在回调,SwiftUI中以编程方式推送View

在我看来,Apple鼓励我们放弃UIViewController在SwiftUI中使用,但如果不使用视图控件,我会觉得有些无能为力。我想要的是能够实现某种ViewModel将事件发送给的功能View

ViewModel

public protocol LoginViewModel: ViewModel {
  var onError: PassthroughSubject<Error, Never> { get }
  var onSuccessLogin: PassthroughSubject<Void, Never> { get }
}
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public struct LoginView: View {
  fileprivate let viewModel: LoginViewModel

  public init(viewModel: LoginViewModel) {
    self.viewModel = viewModel
  }

  public var body: some View {
    NavigationView {
      MasterView()
        .onReceive(self.viewModel.onError, perform: self.handleError(_:))
        .onReceive(self.viewModel.onSuccessLogin, perform: self.handleSuccessfullLogin)
    }
  }

  func handleSuccessfullLogin() {
    //push next screen
  }

  func handleError(_ error: Error) {
    //show alert
  } …
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ios swift swiftui

6
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