我有几个ggplots作为我的ls上的对象.我想将它们保存为单独的文件(虽然我也有兴趣知道如何将它们全部保存在1个大文件中).我读过这个:问题和问题,但我似乎无法适应代码.我也尝试将它们全部放在一个大文件中,如此处所示,但确实得到了这个错误:Error in do.call("grid.arrange", plots2[[i]]) : second argument must be a list.在一个列表中获取所有ggplots时,我遗漏了一些东西.
这是我到目前为止所尝试的:
> ls() #List of objects on my ls. All the p* are my ggplots that I want to save.
[1] "all" "dat" "dat2" "dat3" "data" "dlook" "dlook2" "dlook3" "i" "look2" "mdfx"
[12] "objects" "order" "p" "p1" "p10" "p11" "p12" "p13" "p14" "p15" "p16"
[23] "p17" "p18" "p19" "p2" "p3" "p4" "p5" "p6" "p7" "p8" "p9"
> objects<-ls()
> plot<-objects[14:30]
> …假设您正在使用大型工作环境,并且您不善于跟上环境变量,或者您有一些自动生成批量对象的过程.有没有办法扫描你ls()以识别具有给定类的所有对象？考虑以下简单示例:
#Random objects in my environment
x <- rnorm(100)
y <- rnorm(100)
z <- rnorm(100)
#I estimate some linear models for fun.
lm1 <- lm(y ~ x)
lm2 <- lm(y ~ z)
lm3 <- lm(y ~ x + z)
#Is there a programmatic way to identify all objects in my environment
#that are of the "lm" class? Or really, any arbitrary class?
outList <- list(lm1, lm2, lm3)
#I want to look at a bunch of plots for all …