相关疑难解决方法(0)

我只是想在Java 8中将日期字符串转换为DateTime对象.运行以下行:

DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDateTime dt = LocalDateTime.parse("20140218", formatter);

我收到以下错误:

Exception in thread "main" java.time.format.DateTimeParseException: 
Text '20140218' could not be parsed: 
Unable to obtain LocalDateTime from TemporalAccessor: 
{},ISO resolved to 2014-02-18 of type java.time.format.Parsed
    at java.time.format.DateTimeFormatter.createError(DateTimeFormatter.java:1918)
    at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1853)
    at java.time.LocalDateTime.parse(LocalDateTime.java:492)

语法与此处的建议相同,但我遇到了一个例外.我在用JDK-8u25.

我对 Java 8 还很陌生，所以这个问题可能有一个明显的答案，但在阅读了其他类似的 SO 问题后，我找不到任何导致我的问题的相似之处。

这是我的班级：

import java.time.LocalDateTime;
import java.time.format.DateTimeFormatter;
import java.util.Locale;

public class LocalDateTimeIssue {

    public static void main(String[] args) {
        String dateTimeString = "18-04-2019 12:14:46";
        DateTimeFormatter dtf = DateTimeFormatter.ofPattern("dd-MM-yyyy hh:mm:ss", Locale.US);
        LocalDateTime ldt = LocalDateTime.parse(dateTimeString , dtf);
        System.out.println(ldt.getSecond());
    }

}

这会引发以下异常：

Exception in thread "main" java.time.format.DateTimeParseException: Text '18-04-2019 12:14:46' could not be parsed: Unable to obtain LocalDateTime from TemporalAccessor: {MilliOfSecond=0, MinuteOfHour=14, HourOfAmPm=0, NanoOfSecond=0, MicroOfSecond=0, SecondOfMinute=46},ISO resolved to 2019-04-18 of type java.time.format.Parsed
    at java.time.format.DateTimeFormatter.createError(DateTimeFormatter.java:1920)
    at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1855)
    at java.time.LocalDateTime.parse(LocalDateTime.java:492) …