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如何将新的List <int> {1}放入NUNIT TestCase中?

我有方法:

public static int Add(List<int> numbers)
    {
        if (numbers == null || numbers.Count == 0)
            return 0;

        if (numbers.Count == 1)
            return numbers[0];


        throw new NotImplementedException();
    }
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这是我对它的测试,但它new List<int> {1}在TestCase 中不喜欢:

    [TestCase(new List<int>{1}, 1)]
    public void Add_WithOneNumber_ReturnsNumber(List<int> numbers)
    {

        var result = CalculatorLibrary.CalculatorFunctions.Add(numbers);

        Assert.AreEqual(1, result);
    }
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它给了我错误:

An attribute argument must be a constant expression, typeof expression or array creation expression of an attribute parameter type

我必须这样做:

    [Test]
    public void Add_WithOneNumber_ReturnsNumber()
    {

        var result = CalculatorLibrary.CalculatorFunctions.Add(new List<int>{7});


        Assert.AreEqual(7, …
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c# tdd nunit testcase

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