相关疑难解决方法(0)

试图创建我的第一个graphQL服务器,这是我到目前为止所写的内容.

https://gist.github.com/tharakabimal/7f2947e805e69f67af2b633268db0406

当我尝试按用户名过滤用户时,GraphQL上会弹出以下错误.

GraphQL出错

UserQueriesQL.js中的users字段中发生错误.

我在解析函数上传递参数的方式有什么不对吗？

user: {
type: UserType,
args: { 
  username: {
    name: 'username',
    type: new GraphQLNonNull(GraphQLString)
  }
},
resolve: function(parentValue, args) {
  return User.find( args ).exec();
}

我试图返回一个身份验证令牌,以响应使用用户名和密码作为参数的graphql查询,但不知何故graphql总是返回null.我可以在返回之前打印令牌.

var {
  GraphQLObjectType,
  GraphQLInt,
  GraphQLList,
  GraphQLString,
  GraphQLSchema
} = require('graphql');
let MyUser = require('./modules/user/user');


const Query = new GraphQLObjectType({
  name: 'Query',
  description : 'UserQuery',
  fields: function(){
    return {
      Token :{
        type: GraphQLString,
        description : "Authentication token",
        args: {
          user_name: { type: GraphQLString },
          password: { type: GraphQLString },
        },
        resolve(root, args){
          let user = new MyUser();
          user.authenticateUser(args.user_name, args.password, function(result){
            console.log("token :"+result);
            return result;
          })
        }
      }
    }
  }
});


const Schema = new GraphQLSchema({
  query: Query
}); …

我有一个 GraphQL 驱动的应用程序。查询和变异部分运行良好。我尝试添加 GraphQL 订阅。

服务器 GraphQL 订阅部分代码的灵感来自apollographql/subscriptions-transport-ws的自述文件中的演示。

另请检查代码中的注释以获取更多详细信息。

import Koa from 'koa';
import Router from 'koa-router';
import graphqlHTTP from 'koa-graphql';
import asyncify from 'callback-to-async-iterator';
import { SubscriptionServer } from 'subscriptions-transport-ws';
import firebase from 'firebase-admin';
import { execute, subscribe } from 'graphql';
import { GraphQLObjectType, GraphQLString } from 'graphql';

const MeType = new GraphQLObjectType({
  name: 'Me',
  fields: () => ({
    name: { type: GraphQLString },
    // ...
  }),
});

const listenMe = async (callback) => {
  // Below …

我在服务器端尝试(Apollo)GraphQL并且一直有一个可能很愚蠢的问题.我正在尝试注册用户,但不断收到下面链接图片中显示的错误.问题是什么？忽略非常简单的auth流程,因为我只是测试GraphQl

以下是相关的代码段:

架构

export default `

type User {
    id: ID!
    name: String!
    email: String!
}

type Query {
    allUsers: [User]
  currentUser: User
}

type Mutation {
    createAccount(name: String!, email: String!, password: String!): User
    loginUser(email: String!, password: String!): User
    updatePassword(email: String!, password: String!, newPassword: String!): User
    deleteAccount(email: String!, password: String!): User
}

`

解析器

createAccount: async (
  parent,
  { name, email, password },
  { User },
  info
) => {
  try {
    // Check for invalid (undefined) credentials
    if (!name …

我正在使用 GraphQL 连接到多个 RESTful 端点。我正在编写一个更改来更新用户详细信息，但是 GraphiQL 显示以下响应为 null 而不是更新的用户 ID 和名称...

{
  "data": {
    "updateUser": null
  }
}

  updateUser: (parent, args) => {
    const { id, name } = args;
    return fetch(`${url}/users/${id}`, {
      method: 'PUT',
      body: JSON.stringify({ id, name }),
      headers: { 'Content-Type': 'application/json' },
    })
      .then(res => res.json())
      .then(json => console.log(json));
  },

提前致谢。

我有这个 schema.graphql

### This file was generated by Nexus Schema
### Do not make changes to this file directly


type AuthPayload {
  token: String!
  users: users!
}

scalar DateTime

type Mutation {
  login(email: String, password: String): AuthPayload!
  signup(CREATED_BY: String, EMAIL: String, FIRST_NAME: String, IS_ACTIVE: Boolean, PASSWORD: String, USERNAME: String): AuthPayload!
}

type Query {
  me: users
}

type users {
  CREATED_BY: String!
  CREATED_ON: DateTime
  EMAIL: String!
  FIRST_NAME: String!
  id: Int!
  IS_ACTIVE: Boolean!
  LAST_NAME: String
  MODIFIED_BY: String
  MODIFIED_ON: DateTime
  ORGANIZATION_ID: String …

我有一个待办事项列表，我已经成功地添加了新项目并更新了缓存，现在正在努力添加删除突变。我的最终目标是从删除突变中返回一个 id，该 id 可用于更新客户端的整个待办事项列表。

我尝试将项目的 id 传递给突变，但它返回 null。

图式

type Todo {
  _id: ID!
  todo: String!
}

type RootMutation {
  deleteTodo(_id: ID!): Todo
}

解析器

  deleteTodo: async function({ _id }, req) {
    return await Todo.deleteOne({ _id });
  }

使用以下代码在http://localhost:3000/graphql 的graphql 接口中测试了此突变：

mutation {
  deleteTodo (_id: "example0101010101001010101aasdsadasd"){
        _id
    }
}

出现此错误

{
  "errors": [
    {
      "message": "Cannot return null for non-nullable field Todo._id.",
      "locations": [
        {
          "line": 3,
          "column": 3
        }
      ],
      "path": [
        "deleteTodo",
        "_id"
      ]
    }
  ],
  "data": …

我试图解决研究代码中的一个错误，但失败了。然后我只是尝试启动此代码...

https://github.com/nestjs/nest/tree/master/sample/23-type-graphql

和同样的情况...

错误看起来像

{
  "errors": [
    {
      "message": "Cannot return null for non-nullable field Recipe.id.",
      "locations": [
        {
          "line": 3,
          "column": 5
        }
      ],
      "path": [
        "recipe",
        "id"
      ],
      "extensions": {
        "code": "INTERNAL_SERVER_ERROR",
        "exception": {
          "stacktrace": [
            "Error: Cannot return null for non-nullable field Recipe.id.",
            "    at completeValue (/home/innistry/Downloads/nest-master/sample/23-type-graphql/node_modules/graphql/execution/execute.js:560:13)",
            "    at /home/innistry/Downloads/nest-master/sample/23-type-graphql/node_modules/graphql/execution/execute.js:492:16",
            "    at process._tickCallback (internal/process/next_tick.js:68:7)"
          ]
        }
      }
    }
  ],
  "data": null
}

有人有想法吗？