相关疑难解决方法(0)

如果ajax调用on drop返回失败,我希望draggable恢复到其原始位置.这是我想象的代码..如果在ajax调用正在进行中,draggable可以放在droppable中,这是可以的...

<script type="text/javascript">
jQuery(document).ready($){
    $("#dragMe").draggable();
    $("#dropHere").droppable({
        drop: function(){
            // make ajax call here. check if it returns success.
            // make draggable to return to its old position on failure.
        }
    });
}
</script>
<div id="dragMe">DragMe</div>
<div id="dropHere">DropHere</div>