相关疑难解决方法(0)

我知道如何获得两个平面列表的交集:

b1 = [1,2,3,4,5,9,11,15]
b2 = [4,5,6,7,8]
b3 = [val for val in b1 if val in b2]

要么

def intersect(a, b):
    return list(set(a) & set(b))

print intersect(b1, b2)

但是当我必须找到嵌套列表的交集时,我的问题就开始了:

c1 = [1, 6, 7, 10, 13, 28, 32, 41, 58, 63]
c2 = [[13, 17, 18, 21, 32], [7, 11, 13, 14, 28], [1, 5, 6, 8, 15, 16]]

最后我想收到:

c3 = [[13,32],[7,13,28],[1,6]]

你能帮我个忙吗？

有关

• 在python中展平浅表

这是我的两个清单;

k = [[1, 2], [4], [5, 6, 2], [1, 2], [3], [4], [5,9]]
kDash = [[1, 2], [4], [5, 6, 2], [1, 2], [3], [4], [5,6], [1,2]]

我的输出应该如下;

[[1, 2], [4], [5, 6, 2], [1, 2], [3], [4]]

我怎样才能得到这个输出？

先感谢您