相关疑难解决方法(0)

有没有办法修改闭包内的其中一个变量的绑定值？看一下这个例子来更好地理解它.

def foo():
    var_a = 2
    var_b = 3

    def _closure(x):
        return var_a + var_b + x

    return _closure


localClosure = foo()

# Local closure is now "return 2 + 3 + x"
a = localClosure(1) # 2 + 3 + 1 == 6

# DO SOME MAGIC HERE TO TURN "var_a" of the closure into 0
# ...but what magic? Is this even possible?

# Local closure is now "return 0 + 3 + x"
b = localClosure(1) # …

如果我有:

def f(x):
  def g(y):
    return x + y
  return g

f2 = f(2)

有没有办法找到f2将使用的'x'绑定？我看了检查,但无法判断是否有一些'框架'的东西适用.换句话说,我可以在下面定义一个closedVars():

def closed_vars(anF):
    ... return ...

assert closedVars(f2) == {'x': 2}