相关疑难解决方法(0)

对于读取复杂指针声明,有左右规则.

但是这条规则没有提到如何阅读const修饰语.

例如,在简单的指针声明中,const可以通过多种方式应用:

char *buffer; // non-const pointer to non-const memory
const char *buffer; // non-const pointer to const memory
char const *buffer; // equivalent to previous declartion
char * const buffer = {0}; // const pointer to non-const memory
char * buffer const = {0}; // error
const char * const buffer = {0}; // const pointer to const memory

现在用const指针声明指针怎么样？

char **x; // no const;
const char **x;
char * …