相关疑难解决方法(0)

在这个Q&A中,我编写了一个小包装类,它提供了对范围的反向迭代器访问,依赖于类模板的c ++ 1z语言特征模板参数推导(p0091r3,p0512r0)

#include <iostream>
#include <iterator>
#include <vector>

template<class Rng>
class Reverse
{
    Rng const& rng;    
public:    
    Reverse(Rng const& r) noexcept
    : 
        rng(r)
    {}

    auto begin() const noexcept { using std::end; return std::make_reverse_iterator(end(rng)); }
    auto end()   const noexcept { using std::begin; return std::make_reverse_iterator(begin(rng)); }
};

int main()
{
    std::vector<int> my_stack;
    my_stack.push_back(1);
    my_stack.push_back(2);
    my_stack.puhs_back(3);

    // prints 3,2,1
    for (auto const& elem : Reverse(my_stack)) {
        std::cout << elem << ',';    
    }
}

但是,执行嵌套应用程序Reverse不会产生原始迭代顺序 …