查询运行速度很快:
DECLARE @SessionGUID uniqueidentifier
SET @SessionGUID = 'BCBA333C-B6A1-4155-9833-C495F22EA908'
SELECT *
FROM Report_Opener
WHERE SessionGUID = @SessionGUID
ORDER BY CurrencyTypeOrder, Rank
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但是将相同的SQL放在存储过程中运行速度很慢,并且执行计划完全不同
CREATE PROCEDURE dbo.ViewOpener @SessionGUID uniqueidentifier AS
SELECT *
FROM Report_Opener
WHERE SessionGUID = @SessionGUID
ORDER BY CurrencyTypeOrder, Rank
EXECUTE ViewOpener @SessionGUID
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我跑了
sp_recompile ViewOpener
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它仍然运行相同(严重),我也已将存储过程更改为
CREATE PROCEDURE dbo.ViewOpener @SessionGUID uniqueidentifier AS
SELECT *, 'recompile please'
FROM Report_Opener
WHERE SessionGUID = @SessionGUID
ORDER BY CurrencyTypeOrder, Rank
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然后再回来,试图真正欺骗它重新编译.
我已经删除并重新创建存储过程以使其生成新计划.
我尝试使用一个诱饵变量强制重新编译,并防止参数嗅探:
CREATE PROCEDURE dbo.ViewOpener @SessionGUID uniqueidentifier AS
DECLARE …Run Code Online (Sandbox Code Playgroud) 我正在使用SQL 2005探查器进行一些测试.
我有一个存储过程,它只运行一个SQL查询.
当我运行存储过程时,它需要很长时间并执行800,000次磁盘读取.
当我对存储过程分开运行相同的查询时,它会执行14,000次磁盘读取.
我发现如果我使用OPTION(重新编译)运行相同的查询,则需要800,000次磁盘读取.
由此,我做出(可能是错误的)假设,即存储过程每次都重新编译,这就是导致问题的原因.
任何人都可以对此有所了解吗?
我已经设置了ARITHABORT.(这解决了stackoverflow上的类似问题,但没有解决我的问题)
这是整个存储过程:
CREATE PROCEDURE [dbo].[GET_IF_SETTLEMENT_ADJUSTMENT_REQUIRED]
@Contract_ID int,
@dt_From smalldatetime,
@dt_To smalldatetime,
@Last_Run_Date datetime
AS
BEGIN
DECLARE @rv int
SELECT @rv = (CASE WHEN EXISTS
(
select * from
view_contract_version_last_volume_update
inner join contract_version
on contract_version.contract_version_id = view_contract_version_last_volume_update.contract_version_id
where contract_version.contract_id=@Contract_ID
and volume_date >= @dt_From
and volume_date < @dt_To
and last_write_date > @Last_Run_Date
)
THEN 1 else 0 end)
-- Note that we are RETURNING a value rather than SELECTING it.
-- This means we …Run Code Online (Sandbox Code Playgroud)