相关疑难解决方法(0)

我有以下代码:

url = 'abcdc.com'
print(url.strip('.com'))

我期望: abcdc

我有: abcd

现在我做

url.rsplit('.com', 1)

有没有更好的办法？

Python 2.6 (trunk:66714:66715M, Oct  1 2008, 18:36:04) 
[GCC 4.0.1 (Apple Computer, Inc. build 5370)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> path = "/Volumes/Users"
>>> path.lstrip('/Volume')
's/Users'
>>> path.lstrip('/Volumes')
'Users'
>>> 

我期待输出path.lstrip('/Volumes')应该是/Users